How do I convert ethyl bromide to ethyl iodide?

CH2Br +NaI ⇌ CH3CH2
I + NaBr
Just add ethyl bromide (a.k.a. bromoethane) to anhydrous acetone (a.k.a. propan-2-one) and Sodium Iodide.
The reaction proceeds via an SN2 mechanism and shifts to the right due to the precipitation of NaBr which is almost insoluble in acetone in contrast to sodium iodide which is soluble.

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